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49n^2+10=91
We move all terms to the left:
49n^2+10-(91)=0
We add all the numbers together, and all the variables
49n^2-81=0
a = 49; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·49·(-81)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15876}=126$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*49}=\frac{-126}{98} =-1+2/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*49}=\frac{126}{98} =1+2/7 $
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